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A metal rod of resistance 20Omega is fix...

A metal rod of resistance `20Omega` is fixed along diameter of a conducting ring of radius 0.1m and on x-y plane. There is a magnetic field B=(50t) . The ring roatates with an angular velocity `omega=20rad//s` about its axis. An external resistance resistance `10Omega` is connected cross the centre of the ring an rim. The current through external resistance is

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`e = 1/2 Bl^2 omega = 1/2 xx 50 xx 0.1 xx 0.1 xx 20`
` therefore e = 5V`
Hence the current through the external resistance is
` i = e/R therefore i = 5/15 = 1/3 `amp
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