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The loop ABCD is moving with velocity v ...

The loop ABCD is moving with velocity v towards right. The magnetic field is 4 T. The loop is connected to a resistance of `8Omega`. If steady current of 2 A flows in the loop, then value of v, if loop has resistance of `4Omega`, is (Given, AB = 30 cm, `sin 37^(@)=(3)/(5)`)

Text Solution

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The induced emf in the loop is e = Blv
` e = B(AD) sin 37^@ v - 4 xx 0.3 sin 37^@ v`
Effective resistance of the circuit is R = (4+8)= 12 ohm
Hence i` = e/R = (Blv)/( R)`
` rArr 2 = (4 xx 0.3 xx sin 37^@ mu)/((4+8))`
` therefore v = 100/3 m//s `
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