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The network shown is a part of the close...

The network shown is a part of the closed circuit which the current is changing. At an instant, current in it is 5A. Potential difference between the points A and B if the current is

1) increasing at 1 `A//sec` 2) decreasing at 1`A//sec`

Text Solution

Verified by Experts

1) The coil can be imagined as a cell of emf
` e = L ((di)/(dt)) = 5 xx 1 = 5V`
`therefore ` Equivalent circuit is

`V_A - 5(1) - 15 + 5 = V_B`
Hence `V_A - V_B = 5+15 - 5 = 15V`
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