Home
Class 12
PHYSICS
An inductor of 10mH is connected to a 18...

An inductor of 10mH is connected to a 18V battery through a resistor of 10k`Omega` and a switch After a long time, when the maximum current is set up in the circuit, the current is switched off. Calculate the cur- rent in the circuit after 2 `mu`s.

Text Solution

Verified by Experts

Given that
`L = 10mH = 10^(-2) H, R = 10 k Omega = 10^4 Omega`
and E = 18V , we know that
`I_0 = E/R = (18)/(10^4) A = 18 xx 10^(-4)A `
Time constant , `tau_L = L/R = (10 xx 10^(-3))/(10 xx 10^3) = 10^(-6)` sec
We know that , `I = I_0 e^(-(R//L)t)`
here `t = 2 mus = 2xx 10^(-6)S, I_0 = 18 xx 10^(-4)A`
`I = 18 xx 10^(-4) = 2.48 xx 10^(-4)A`
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC INDUCTION

    AAKASH SERIES|Exercise EXERCISE-IA|58 Videos

  • ELECTROMAGNETIC INDUCTION

    AAKASH SERIES|Exercise EXERCISE-IB|18 Videos

  • ELECTRIC FIELD AND POTENTIAL

    AAKASH SERIES|Exercise PROBLEMS (LEVEL-II)|26 Videos

  • ELECTROMAGNETIC WAVES

    AAKASH SERIES|Exercise EXERCISE -II|22 Videos

Similar Questions

Explore conceptually related problems

An inductor of 10mH is connected to a 18V battery through a resistor of 10 kOmega and a switch. After a long time, when the maximum current is set up in the circuit, the battery is disconnected from the circuit. Calculate the current in the circuit after 15mu s

An inductor of 3H is connected to a battery of emf 6V through a resistance of 100 Omega . Calculate the time constant. What will be the maximum value of current in the circuit ?

An idal coil of 10 is connected in series with a resitance of 5Omega and a battery of 5V. After 2s, after the connection is made, the current flowing ( in ampere) in the circuit is

A coil of inductance L=50muH and resistance = 0.5Omega is connected to a battery of emf = 5V. A resistance of 10Omega is connected parallel to the coil. Now, at the same instant the connection of the battery is switched off. Then, the amount of heat generated in the coil after switching off the battery is

An inductor (L =20 mH) , a resistor ( R = 100 Omega) and a battery (epsilon = 10 V) are connected in series. After along time the circuit is short- circuited and then the battery is disconnected. Find the current in the circuit 1ms after short- circuiting.

An L-R circuit has a cell of e.m.f. E , which is switched on at time t = 0. The current in the circuit after a long time will be

Two resistors, with resistance 10 Omega and 15 Omega , are to be connected to a battery of e.m.f. 12 V so as to obtain : (i) minimum current (ii) maximum current (a) Describe the mode of connecting the resistances in each case. (b) Calculate the strength of the total current in the circuit in each case.

An inductor (L = 100 mH), a resistor (R = 100Omega) and a battery (E = 100 V) are initially connected in series as shown in the figure. After a long time the battery is disconnected after short circuiting the points A and B. The current in the circuit 1 ms after the short circuit is

An inductor L and a resistor R are connected in series to a battery, through a key/switch. Show graphically, how current decreases with time when the key/switch is opened.

An inductor of inductance 10 mH and a resistance of 5 is connected to a battery of 20 V at t = 0. Find the ratio of current in circuit at t =  to current at t = 40 sec