Home
Class 12
PHYSICS
(A): The working of dynamo is based on t...

(A): The working of dynamo is based on the principle of self induction.
(R) : Self induction of a coil is numerically equal to the magnetic flux linked with the coil, when a unit current flow through it.

A

Both .A. and .R. are true and .R. is the correct explanation of .A.

B

Both .A. and .R. are true and .R. is not the correct explanation of .A.

C

.A. is true and .R. is false

D

.A. is false and .R. is true

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC INDUCTION

    AAKASH SERIES|Exercise EXERCISE - II (MAGNETIC FLUX, FARADAY.S LAW, LENZ.S LAW , AC GENERATOR)|10 Videos

  • ELECTROMAGNETIC INDUCTION

    AAKASH SERIES|Exercise EXERCISE - II (MOTIONAL EMF)|3 Videos

  • ELECTROMAGNETIC INDUCTION

    AAKASH SERIES|Exercise EXERCISE - I (SELF AND MUTUAL INDUCTION)|16 Videos

  • ELECTRIC FIELD AND POTENTIAL

    AAKASH SERIES|Exercise PROBLEMS (LEVEL-II)|26 Videos

  • ELECTROMAGNETIC WAVES

    AAKASH SERIES|Exercise EXERCISE -II|22 Videos

Similar Questions

Explore conceptually related problems

A coil has an inductance 0.05 H and 100 turns. Calculate the flux linked with it when 0.02A current is passed through it.

Assertion : An ac generator is based on the self inductance of the coil. Reason : Self inductance involves two coils.

The self inductance of a coil having 400 turns is 10 mH. The magnetic flux through the cross section of the coil corresponding to current 2 mA is

Define self-inductance of a coil . Write its S.I. units ?

Define self-inductance of a coil . Write its S.I. units ?

The self-inductane of a coil having 500 turns is 50 mH. The magnetic flux through the cross-sectional area of the coil while current through it is 8 mA is found to be

A coil of self-inductance L is placed in an external magnetic field (no current flows in the coil). The total magnetic flux linked with the coil is phi . The magnetic field energy stored in the coil is

Two coils of self inductance 100 mH and 400 mH are placed very closed to each other. Find maximum mutual inductance between the two when 4 A current passes through them.

Two coils of self inductance 100 mH and 400 mH are placed very closed to each other. Find maximum mutual inductance between the two when 4 A current passes through them.

The moving coil of a galvanometer 4 cm long and 1.5 cm wide, made of 200 turns of thin wire, works in a magnetic field with induction of 0.1 T. The plane of the coil is parallel to lines of induction. Find the torque acting on the coil when a current of 1 mA flows in it.