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Let there are three equal masses situate...

Let there are three equal masses situated at the vertices of an equilateral triangle, as shown in Fig. Now particle `A` starts with a velocity `v_(1)` towards line `AB`, particle `B` starts with the velocity `v_(2)`, towards line `BC` and particle `C` starts with velocity `v_(3)` towards line `CA`. Find the displacement of the centre of mass of the three particles `A, B` and `C` after time `t`. What would it be if `v_(1)=v_(2)=v_(3)`?

A

Zero

B

`(v_(1)+v_(2)+v_(3))/(3)`

C

`(v_(1)+(sqrt(3))/(2)v_(2)+(v_(3))/(2))/(3)`

D

`(v_(1)+v_(2)+v_(3))/(4)`

Text Solution

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The correct Answer is:
A
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