Home
Class 12
PHYSICS
A carrier wave of 1000 W is subjected to...

A carrier wave of 1000 W is subjected to `100%` modulation. Calculate (i) Power of modulated wave, (ii) Power in USB, (iii) Power in LSB.

Text Solution

AI Generated Solution

To solve the problem, we will follow these steps: ### Step 1: Understand the given information - The power of the carrier wave (PC) = 1000 W - The modulation index (m) for 100% modulation = 1 (since 100% modulation means m = 100/100) ### Step 2: Calculate the power of the modulated wave (Pt) The formula for the power of the modulated wave is given by: ...
Promotional Banner

Topper's Solved these Questions

  • COMMUNICATION SYSTEMS

    AAKASH SERIES|Exercise EXERCISE-I (Antenna)|7 Videos
  • COMMUNICATION SYSTEMS

    AAKASH SERIES|Exercise EXERCISE-I (Modulation)|17 Videos
  • COMMUNICATION SYSTEMS

    AAKASH SERIES|Exercise Exercise - III (Modulation & Power)|9 Videos
  • COMMUNICATION SYSTEM

    AAKASH SERIES|Exercise LECTURE SHEET (LEVEL - I) (MAIN) (EXERCISE - IV) (Straight Objective & More than one Correct Answer Type Questions)|20 Videos
  • CURRENT ELECTRICITY

    AAKASH SERIES|Exercise PROBLEMS (LEVEL-II)|27 Videos

Similar Questions

Explore conceptually related problems

A 400 W carrier wave is modulated to a depth of 75%. Calculate the total power in the modulated wave.

A 300W carrier is modulated to a depth 75%. The total power in the modulated wave is

An AM wave has 1800 watt of total power content, For 100% modulation the carrier should have power content equal to

A 100 V carrier wave is mode to vary betqeen 160 and 40 V by a modulating signal . What is the modulation index ?

An audio signal is modulated by a carrier wave of 20 MHz such that the bandwidth required for modulation is 3 kHz. Could this wave be demodulated by a diode detector which has the values of R and C as (i) R = 1 k Omega, C = 0.01 mu F (ii) R = 10 k Omega, C = 0.01 muF (iii) R = 10k Omega , C = 1 mu muF .

An audio signal is modulated by a carrier wave of 20 MHz such that the bandwidth required for modulation is 3 kHz. Could this wave be demodulated by a diode detector which has the values of R and C as (i) R = 1 k Omega, C = 0.01 mu F (ii) R = 10 k Omega, C = 0.01 muF (iii) R = 10k Omega , C = 1 mu muF .

If the percentage of modulation is 50% then the useful power in the AM wave is

A carrier wave of amplitude A is used to modulate (amplitude) the signal.Modulated signal amplitude swings from 0.1 A to 1.9A,calculate modulation index.

A carrier wave of amplitude A is used to modulate (amplitude) the signal.Modulated signal amplitude swings from 0.1 A to 1.9A,calculate modulation index.