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The amplitude of the modulating wave is ...

The amplitude of the modulating wave is `2//5` th of the amplitude of the carrier wave. The percentage modulation

A

20

B

40

C

50

D

60

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The correct Answer is:
To solve the problem, we need to find the percentage modulation given that the amplitude of the modulating wave is \( \frac{2}{5} \) of the amplitude of the carrier wave. Here’s a step-by-step solution: ### Step 1: Understand the relationship between amplitudes Let: - \( A_c \) = Amplitude of the carrier wave - \( A_m \) = Amplitude of the modulating wave According to the problem, the relationship between the amplitudes is given by: \[ A_m = \frac{2}{5} A_c \] ### Step 2: Calculate the modulation index The modulation index \( m \) is defined as the ratio of the amplitude of the modulating wave to the amplitude of the carrier wave: \[ m = \frac{A_m}{A_c} \] Substituting the values we have: \[ m = \frac{2/5 A_c}{A_c} = \frac{2}{5} \] ### Step 3: Convert modulation index to percentage modulation Percentage modulation is calculated using the formula: \[ \text{Percentage Modulation} = m \times 100 \] Substituting the value of \( m \): \[ \text{Percentage Modulation} = \frac{2}{5} \times 100 \] ### Step 4: Perform the calculation Calculating the above expression: \[ \text{Percentage Modulation} = 0.4 \times 100 = 40\% \] ### Final Answer The percentage modulation is \( 40\% \). ---
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