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A metal block of area 0.10m^(2) is conne...

A metal block of area `0.10m^(2)` is connected to a 0.010 kg mass via a string that passes over an ideal pulley (cosidered massless and frictionless). As in figure. A liquid with a film thickness of 0.30 mm is placed b etween the block and the table. when released the block moves to the right with a constant speed of `0.085ms^(-1)`. find the coefficient of viscosity of the liquid.

Text Solution

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The metal block moves to the right because of the tension in the string. The tension T is equal in magnitude to the weight of the suspended mass m. Thus the shear force F is
Shear stress on the fluit `F//A=(9.8xx10^(-2))/(0.10)`
= stain rate = `(v)/(t)=(0.085ms^(-1))/(0.3xx10^(-3)m)`
`eta=("stress")/("strainrate")=3.45xx10^(-3)"Pa s"`
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