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A small steel ball falls through a syrup...

A small steel ball falls through a syrup at a constant speed of 1.0 m/s. If the steel balls is pulled upwards with a force equal to twice its effective weight, how fast will it move upwards ?

Text Solution

Verified by Experts

`W_(e)` = effective weight
In equilibrium, `kv=w_(e)`
Again, `2w_(e)-w_(e)=kv^(1)`
From Eqs. (i) and (ii)
`v^(1)=v=1.0m//s`
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