The lower end of a capillary tube of dia...

The lower end of a capillary tube of diameter 2.00 mm is dipped 8.00 cm below the surface of water is a beaker. What is the pressure required in the tube in order to blow a hemispherical bubble at its end in water? The surface tension of water at temperature of the experiments is `7.30xx10^(-2)Pa`, density of water `=1000kg//m^(3)`, `g=9.80ms^(-2)`, also calculate the excess pressure.

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The excess pressure in a bubble of gas in a liquid is given by `2S//r`, where S is the surface tension of the liquid-gas interface. You should note there is only one liquid surface in thiscase. The radius of the bubble is r. Now the pressure outside the bubble, `p_("out")` equals atmospheric pressure plus the pressure due to 8.00cm of water column.
`P_("out")=(1.01xx10^(5)+0.08xx1000xx9.80)Pa`
`=1.01784xx10^(5)Pa`
Therefore, the pressure inside the bubble is
`P_("in")=P_("out")+2S//r=1.01784xx10^(5)+(2xx7.3xx10^(-2)//10^(-3))`
`=(1.01784+0.00146)xx10^(5)=1.02xx10^(5)Pa`

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