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Two chamber containing m(1) and m(2) gra...

Two chamber containing `m_(1)` and `m_(2)` grams of a gas at pressures `P_(1) andP_(2)` respectively are put in communication with each other, temperature remaining constant. The common pressure reached will be

Text Solution

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According to Boyle.s law `P/rho` = constant
`thereforeV_(1)=m_(1)/rho_(1)=(km_(1))/P_(1)andV_(2)=(km_(2))/P_(2)`
Total volume = `k(m_(1)/P_(1)+m_(2)/P_(2))`
Let mixture has common pressure P and common density `rho`.
`rho=((m_(1)+m_(2)))/(k(m_(1)/P_(1)+m_(2)/P_(2)))`
`rArrP=krho=((m_(1)+m_(2))/(m_(1)/P_(1)+m_(2)/P_(2)))=(P_(1)P_(2)(m_(1)+m_(2)))/((P_(2)m_(1)+m_(2)P_(1)))`
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