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Consider the situation shown in figure. ...

Consider the situation shown in figure. The frame is made of the same material and has a uniform cross-section area everywhere. Calculate the amount of heat flowing per second through a cross section of the bent part if the total heat taken out per second from the end at `100^(@)C` is `130J` .

Text Solution

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The rods BE, of length 60 cm and the bent part BCDE of length 70 cm are parallel between B and C.
The rate of flow q = `KA(d theta)/l t`.
Here `qprop1/lq_(1)/q_(2)=l_(2)/l_(1)=70/60=7/6`
The flow of heat through bent part is
`q_(1)=7/13xx130=70J`
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