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Density of liquid at any temperature 't'...

Density of liquid at any temperature 't' is given by `d_(t)=d_(0)//(1+g t)`. This equation applies to

A

all liquids

B

all liquids except water

C

no liquid

D

all liquids except mercury

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To solve the question regarding the density of a liquid at any temperature 't', given by the equation: \[ d_t = \frac{d_0}{1 + gt} \] we need to analyze the context of this equation and its applicability to different types of liquids. ### Step-by-Step Solution: 1. **Understanding the Equation**: - The equation states that the density \( d_t \) of a liquid at temperature \( t \) is equal to the initial density \( d_0 \) divided by \( 1 + gt \), where \( g \) is a constant that represents the coefficient of volume expansion of the liquid. 2. **Analyzing the Variables**: - \( d_0 \): Density of the liquid at a reference temperature (usually at 0 degrees Celsius). - \( g \): Coefficient of volume expansion, which is a property of the liquid that indicates how much the volume changes with temperature. - \( t \): The temperature at which we want to find the density. 3. **Identifying the Applicability**: - This equation is generally applicable to most liquids, as they tend to expand uniformly with temperature, leading to a decrease in density as temperature increases. - However, water exhibits an anomalous behavior, particularly between 0 degrees Celsius and 4 degrees Celsius, where it actually contracts instead of expanding. This means that the relationship described by the equation does not hold true for water in that temperature range. 4. **Conclusion**: - Since the equation does not apply to water due to its unique properties, we can conclude that the equation is valid for all liquids except water. ### Final Answer: The equation applies to **all liquids except water**.
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