A solid is suspended in a liquid. If the liquid is heated, the solid (assume the solid expansion is negligible)

Options

A. floats
B. sinks
C. no change
D. nothing can be said

Answer

To solve the problem, we need to analyze the behavior of a solid suspended in a liquid when the liquid is heated, considering that the expansion of the solid is negligible.

### Step-by-Step Solution:

1. **Understanding the Setup**:
- We have a solid object suspended in a liquid.
- The solid does not expand significantly when the temperature of the liquid changes.

2. **Effect of Heating the Liquid**:
- When the liquid is heated, it undergoes thermal expansion. This means that the volume of the liquid increases as its temperature rises.

3. **Density Changes**:
- Density (\( \rho \)) is defined as mass (\( m \)) divided by volume (\( V \)):
\[ \rho = \frac{m}{V} \]
- Since the mass of the liquid remains constant while its volume increases due to heating, the density of the liquid will decrease.

4. **Comparison of Densities**:
- The density of the solid remains constant because its volume does not change (negligible expansion).
- As the liquid's density decreases, we can compare the densities of the solid and the liquid.

5. **Determining the Behavior of the Solid**:
- If the density of the solid is greater than the density of the liquid, the solid will sink.
- If the density of the solid is less than the density of the liquid, the solid will float.
- Since we established that the density of the liquid decreases while the density of the solid remains constant, the solid will have a greater density than the liquid.

6. **Conclusion**:
- Therefore, the solid will sink in the liquid when the liquid is heated.

### Final Answer:
The solid will **sink** in the liquid when the liquid is heated.