Home
Class 11
PHYSICS
Passage I) In simple harmonic motion for...

Passage I) In simple harmonic motion force acting on a particle is given as `F=-4x`, total mechanical energy of the particle is 10 J and amplitude of oscillations is 2m, At time t=0 acceleration of the particle is `-16m/s^(2)`. Mass of the particle is 0.5 kg.
Displacement time equation equation of the particle is

A

`x = 2 sin 2 t`

B

`x = 2 sin 4 t`

C

`x = 2 cos 2 t`

D

`x = 2 cos (2 sqrt(2) t)`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

Passage I) In simple harmonic motion force acting on a particle is given as F=-4x , total mechanical energy of the particle is 10 J and amplitude of oscillations is 2m, At time t=0 acceleration of the particle is -16m/s^(2) . Mass of the particle is 0.5 kg. At x=+1m, potential energy and kinetic energy of the particle are

Passage I) In simple harmonic motion force acting on a particle is given as F=-4x , total mechanical energy of the particle is 10 J and amplitude of oscillations is 2m, At time t=0 acceleration of the particle is -16m/s^(2) . Mass of the particle is 0.5 kg. Potential energy of the particle at mean position is

Force acting on a particle is F=-8x in S.H.M. The amplitude of oscillation is 2 (in m) and mass of the particle is 0.5 kg. The total mechanical energy of the particle is 20 J. Find the potential energy of the particle in mean position (in J).

Two simple harmonic motions y_(1) = Asinomegat and y_(2) = Acos omega t are superimposed on a particle of mass m. The total mechanical energy of the particle is

Kinetic energy of a particle moving in a straight line varies with time t as K = 4t^(2) . The force acting on the particle

If particle is excuting simple harmonic motion with time period T, then the time period of its total mechanical energy is :-

A time varying force, F=2t is acting on a particle of mass 2kg moving along x-axis. velocity of the particle is 4m//s along negative x-axis at time t=0 . Find the velocity of the particle at the end of 4s.

The x-t graph of a particle undergoing simple harmonic motion is shown below. The acceleration of the particle at t = 2/3s is

The velocity time relation of a particle is given by v = (3t^(2) -2t-1) m//s Calculate the position and acceleration of the particle when velocity of the particle is zero . Given the initial position of the particle is 5m .

A particle executing simple harmonic motion with an amplitude 5 cm and a time period 0.2 s. the velocity and acceleration of the particle when the displacement is 5 cm is