Home
Class 11
PHYSICS
A bullet of mass m moving with velocity ...

A bullet of mass m moving with velocity u passes through a wooden block of mass M=nm. The block is resting on a smooth horizontal floor. After passing through the block the velocity of bullet is v. Its velocity relative to block is

Text Solution

Verified by Experts

`m u =mv + mn v ^(-1) (or) v ^(1) = ((u -v)/( n)) therefore` velocity of bullet relative to block will be
`v _(r) = v - v ^(i) = v - ((u-v)/( n)) = ((1+n)v -u)/( n )`
Promotional Banner

Similar Questions

Explore conceptually related problems

A bullet of mass 'm' moving with velocity 'u' passes through a wooden block of mass M = nm as shown in figure. The block is resting on a smooth horizontal floor. After passing through the block, velocity relative to the block is .

A bullet of mass m moving with velocity v strikes a suspended wooden block of mass M . If the block rises to a height h , the initial velocity of the block will be ?

A bullet of mass m and velocity v is fired into a large block of mass M . The final velocity of the system is

A bullet of mass m moving with velocity upsilon_(1) strikes a suspended wooden block of mass M as shown in the figure and sticks to it. If the block rises to a height y. the initial of the bullet is

A bullet of mass m moving with velocity v strikes a block of mass M at rest and gets embedded into it. The kinetic energy of the composite block will be

A bullet of mass 50g moving with velocity 600m//s hits block of mass 1.0kg placed on a rough horizontal ground and comes out of the block with a velocity of 400m//s . The coefficient of friction between the block and the ground is 0.25 . Neglect loss of mass of the block as the bullet pierces through it. (a) In spite of the fact that friction acts a an external force, can you apply principle of conservation of momentum during interaction of the ullet with the block? (b) Find velocity of the block immediately after the bullet pierces through it. (c)FInd the distance the block will travel before it stops.

If a bullet of mass 5g moving withg a velocity of 100m/s penetrates a wooden block upto 6cm . Find the average force imposed .

A force P acts on a smooth block of mass m placed on a horizontal floor at an angle theta with with horizontal on the block

If a bullet of mass 5gm moving with velocity 100m/sec, penertates the wooden block upto 6cm. Then the average force imposed by the bullet on the block is

A bullet weighing 10 g and moving with a velocity 300 m/s strikes a 5 kg block of ice and drop dead. The ice block is kept on smooth surface. The speed of the block after the the collision is