Home
Class 11
PHYSICS
Find the binding energy of a satellite o...

Find the binding energy of a satellite of mass `m` in orbit of radius `r`, (R = radius of earth, g = acceleration due to gravity)

A

`(mgR^(2))/r`

B

`(mgR^(2))/(2r)`

C

`-(mgR^(2))/r`

D

`-(mgR^(2))/(2r)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

A satellite of mass m is moving in a circular or orbit of radius R around the earth. The radius of the earth is r and the acceleration due to gravity at the surface of the earth is g. Obtain expressions for the following : (a) The acceleration due to gravity at a distance R from the centre of the earth (b) The linear speed of the satellite (c ) The time period of the satellite

A particle of mass 'm' is raised to a height h = R from the surface of earth. Find increase in potential energy. R = radius of earth. g = acceleration due to gravity on the surface of earth.

Periodic time of a satellite revolving above Earth's surface at a height equal to R, radius of Earth, is : [g is acceleration due to gravity at Earth's surface]

A body of mass m is raised to a height 10 R from the surface of the earth, where R is the radius of the earth. Find the increase in potential energy. (G = universal constant of gravitational, M = mass of the earth and g= acceleration due to gravity)

A body of mass m is raised to a height 10 R from the surface of the earth, where R is the radius of the earth. Find the increase in potential energy. (G = universal constant of gravitational, M = mass of the earth and g= acceleration due to gravity)

An artificial satellite is moving in a circular orbit around the earth with a speed equal to half the magnitude of escape velocity from the surface of earth. R is the radius of earth and g is acceleration due to gravity at the surface of earth. (R=6400 km). The time period of revolution of satellite in the given orbit is

An artificial satellite is moving in circular orbit around the earth with speed equal to half the magnitude of escape velocity from the surface of earth. R is the radius of earth and g is acceleration due to gravity at the surface of earth (R = 6400km) Then the distance of satelite from the surface of earth is .

A particle of mass 'm' is raised from the surface of earth to a height h = 2R. Find work done by some external agent in the process. Here, R is the radius of earth and g the acceleration due to gravity on earth's surface.

Assuming the mass of Earth to be ten times the mass of Mars, its radius to be twice the radius of Mars and the acceleration due to gravity on the surface of Earth is 10 m//s^(2) . Then the accelration due to gravity on the surface of Mars is given by

A small body of mass m falls to the earth from infintie distance away. What will be its velocity or reaching the earth? (Radius of the earth = R, acceleration due to gravity on the surface of the earth is g) :-