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A force F is applied at the top of a rin...

A force F is applied at the top of a ring of mass M and radius R placed on a rough horizontal surface as shown in figure. Friction is sufficient to prevent slipping. The friction force acting on the ring is

Text Solution

Verified by Experts

`alpha=(tau)/(I)=(F(2R))/(2MR^(2))=(F)/(MR)`
Now `F+f=Ma=MRalpha` = F or f=0
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