Home
Class 11
PHYSICS
Unit mass of a liquid of volume V(1) com...

Unit mass of a liquid of volume `V_(1)` completely turns into a gas of volume `V_(2)` at constant atmoshpheric pressure `p_(0)` and temperature T. The latent heat of vaporization is L. Then the change in internal energy of the gas is

A

`pV_(2)-pV_(1)`

B

`L - pV_(2)+pV_(1)`

C

zero

D

`L +pV_(2)-pV_(1)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

Unit mass of liquid of volume V_(1) completely turns into a gas of volume V_(2) at constant atmospheric pressure P and temperature T. The latent heat of vaporization is "L". Then the change in internal energy of the gas is

A gas of volume changes 2 litre to 10 litre at constant temperature 300K, then the change in internal energy will be :

Two moles of a gas at temperature T and volume V are heated to twice its volume at constant pressure. If (C _(p))/(C _(v)) = gamma then increase in internal energy of the gas is-

An ideal gas is found to obey the law V^2T = constant . The initial pressure and temperature are P_0 and T_0 . If gas expands such that its pressure becomes (P_0)/4 , then the final temperature of the gas will be

Two moles of an ideal monoatomic gas, initially at pressure p_1 and volume V_1 , undergo an adiabatic compression until its volume is V_2 . Then the gas is given heat Q at constant volume V_2 . (i) Sketch the complete process on a p-V diagram. (b) Find the total work done by the gas, the total change in its internal energy and the final temperature of the gas. [Give your answer in terms of p_1,V_1,V_2, Q and R ]

If a gas of a volume V_(1) at pressure p_(1) is compressed adiabatically to volume V_(2) and pressure p_(2) , calculate the work done by the gas.

A monatomic gas on n molecules is heated from temperature T_(1) to T_(2) under two different conditions (i) constant volume, (ii) constant pressure. The change of internal energy of the gas

A monoatomic gas at a temperature T has pressure P and heat energy per unit volume E. then

An ideal gas ((C_(p))/(C_(v))=gamma) has initial volume V_(0) is kept in a vessel. It undergoes a change and follows the following relation P = kV^(2) (where P is pressure, and V is volume) find the change in internal energy of the gas if its final pressure is P_(0) :

An inflated rubber balloon contains one mole of an ideal gas has a pressure p, volume V and temperature T. if the temperature rises to 1.1 T, and the volume is increased to 1.05 V, the final pressure will be