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A satellite orbits the earth at a distan...

A satellite orbits the earth at a distance equal to the radius of the earth above its surface. Find (i) its speed and (ii) its period

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To solve the problem of finding the speed and period of a satellite orbiting the Earth at a distance equal to the radius of the Earth above its surface, we can follow these steps: ### Given Data: - Radius of the Earth (R) = 6400 km = 6.4 × 10^6 m - Height of the satellite above the surface = R = 6400 km - Therefore, the total distance from the center of the Earth (d) = R + height = 6400 km + 6400 km = 12800 km = 1.28 × 10^7 m - Gravitational constant (G) = 6.67 × 10^(-11) N m²/kg² - Mass of the Earth (M) = 6 × 10^(24) kg ...
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