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A U-tube is supported with its limbs ver...

A U-tube is supported with its limbs vertical and is partly filled with water. If internal diameters of the limbs are `1xx10^(-2)mand1xx10^(-4)m` respectively, what will be the difference in height of water in the two limbs ? Surface tension of water is `0.07Nm^(-1)` ?

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To solve the problem of finding the difference in height of water in the two limbs of a U-tube, we can follow these steps: ### Step 1: Identify the given data - Internal diameter of limb 1, \( d_1 = 1 \times 10^{-2} \, \text{m} \) - Internal diameter of limb 2, \( d_2 = 1 \times 10^{-4} \, \text{m} \) - Surface tension of water, \( \sigma = 0.07 \, \text{N/m} \) - Density of water, \( \rho = 10^3 \, \text{kg/m}^3 \) - Acceleration due to gravity, \( g = 9.8 \, \text{m/s}^2 \) ...
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