A capillary tube immersed in water is taken to moon, where the value of acceleration of gravity is g/6. What happens to the rise of the liquid (h) on the moon?

Explanation

To solve the problem of what happens to the rise of liquid (h) in a capillary tube when taken to the moon, where the acceleration due to gravity is \( g/6 \), we can follow these steps:

### Step 1: Understand the relationship between height of liquid rise and gravity
The height to which a liquid rises in a capillary tube is given by the formula:
\[ h = \frac{2 \gamma \cos \theta}{\rho g r} \]
where:
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