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Two vectors vecA and vecB have equal mag...

Two vectors `vecA` and `vecB` have equal magnitudes. The magnitude of `(vecA+vecB)` is n times the magnitude of `(vecA-vecB)`. The angle between `vecA` and `vecB` is :

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`|vec(A)+ vec(B)| = n|vec(A) - vec(B)|`
`2A cos""(theta)/(2) = n2A sin""(theta)/(2)(A=B)`
`therefore tan""(theta)/(2) = (1)/(n), (theta)/(2) = tan^(-1)((1)/(n)), theta = 2 tan^(-1)((1)/(n))`
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