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A particle is projected from a towaer as...

A particle is projected from a towaer as shown in figure, then the distance from the foot of the tower where it will strike the ground will be :- `("take "g=10 m//s^(2))`

Text Solution

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`s = u t + (1)/(2) a t^(2)`
`1500 = (500)/(3) sin 37 + (1)/(2) 10 xx t^(2)`
`1500 = (500)/(3) xx (3)/(5) t + 5t^(2)`
`300 = 20t + t^(2)`
On solving, t = 10 s
`therefore` horizontal distance `= u cos theta. T`
`= (500)/(3) xx (4)/(5) xx 10 = (4000)/(3)m`
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