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A body is projected with velocity 'u' so...

A body is projected with velocity 'u' so that the maximum height is thrice the horizontal range. Then the maximum height is

A

`(72 u^(2))/(145 g)`

B

`(6)/(sqrt(145))(u^(2))/(g)`

C

`(u^(2))/(2g)`

D

`(145)/(72)(u^(2))/(g)`

Text Solution

Verified by Experts

The correct Answer is:
A
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