If a raindrop falls under the influence of the downward gravitational force and the opposing resistive force. Consider a drop of mass 1.00 g falling from a height 1.00 km. It hits the ground with a speed of `50.0 ms^(-1)`. (1) What is the work done by the gravitational force ? (2) What is the work done by the unknown resistive force ?

Explanation

To solve the problem step-by-step, we will calculate the work done by the gravitational force and the work done by the resistive force acting on the raindrop.

### Given Data:
- Mass of the raindrop, \( m = 1.00 \, \text{g} = 1.00 \times 10^{-3} \, \text{kg} \)
- Height from which it falls, \( h = 1.00 \, \text{km} = 1.00 \times 10^{3} \, \text{m} \)
- Final speed when it hits the ground, \( v_f = 50.0 \, \text{m/s} \)
- Initial speed, \( v_i = 0 \, \text{m/s} \) (since it starts from rest)
- Acceleration due to gravity, \( g = 10 \, \text{m/s}^2 \)
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