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A man standing on the edge of a roof of a 20 m tall building projects a ball of mass 100 g vertically up with a speed of `10 ms^(-1)` and simultaneously throws another ball of same mass vertically down with the same speed. Find the kinetic energy of each ball when they reach the ground. `(g=10 ms^(-2))`

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To solve the problem, we need to find the kinetic energy of each ball when they reach the ground. We will analyze both balls separately, but they will have the same kinetic energy upon reaching the ground due to the conservation of energy principles. ### Step-by-Step Solution: 1. **Identify the given data:** - Height of the building (h) = 20 m - Mass of each ball (m) = 100 g = 0.1 kg (convert grams to kilograms) - Initial velocity of the ball thrown upwards (u_up) = 10 m/s ...
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