Home
Class 11
PHYSICS
Find the angle .theta. with the lower ve...

Find the angle `.theta.` with the lower vertical at which the resultant acceleration of the bob is along the horizontal, when the perpendicular is released from horizontal position.

Text Solution

AI Generated Solution

To solve the problem of finding the angle \(\theta\) with the lower vertical at which the resultant acceleration of the bob is horizontal, we will follow these steps: ### Step 1: Understand the forces acting on the bob When the bob is released from the horizontal position, it experiences two types of acceleration: 1. **Centripetal acceleration (\(a_c\))**: directed towards the center of the circular path. 2. **Tangential acceleration (\(a_t\))**: directed along the path of motion. ### Step 2: Set up the geometry ...
Promotional Banner

Similar Questions

Explore conceptually related problems

A uniform rod of mass m and length l can rotate in a vertical plane about a smooth horizontal axis point H . a. Find angular acceleration alpha of the rod. just after it is released from initial horizontal position from rest'? b. Calculate the acceleration (tangential and radial) , point A at this moment.

A uniform rod of mass m and length l can rotate in vertical plane about a smooth horizontal axis hinged at point H . Find angular acceleration alpha of the rod just after it is released from initial position making an angle of 37^@ with horizontal from rest?

A uniform rod of length L and mass M is pivoted freely at one end and placed in vertical position. a. What is angular acceleration of the rod when it is at ann angle theta with the vertical? b. What is the tangential linear acceleration of the free end when the rod is horizontal?

A block is placed on a smooth wedge of inclination angle theta with the horizontal. What minimum acceleration should be given to the wedge in the horizontal direction so that the block starts moving up along the incline?

In the figure given in the text if mass of the rod is m then find hinge force. (a). Just after the rod is released from the horizontal position. (b). When rod becomes vertical

A uniform disc of mass m and radius R is pivoted at point P and is free rotate in vertical plane. The centre C of disc is initially in horizontal position with P as shown in figure. If it is released from this position, then its angular acceleration when the line PC is inclined to the horizontal at an angle theta is

A uniform rod of maass m and length L is placed on the fixed cylindrical surface of radius R at an small angular position theta from the vertical (vertical means line joining centre and vertex of the cylindrical path) as shown in the figure and released from rest. Find the angular velocity omega of the rod at the instant when it crosses the horizontal position (Assume that when rod comes at horizontal position its mid point and vertex of the circular surface coincide). Friction is sufficient to prevent any slipping.

The angle which the free surface of a liquid filled in a container will make with horizontal if the container is accelerated horizontally with acceleration (g)/(sqrt(3)) is

A disc of a mass M and radius R can rotate freely in vertical plane about a horizontal axis at O . Distant r from the center of disc as shown in the figure. The disc is released from rest in the shown position. The angular acceleration of disc when OC rotates by an angles of 37^(@) is

A bob suspended from the ceiling of a car which is accelerating on a horizontal road. The bob stays t rest with respect to the car when the string is making an angle theta with the vertical.The linear momentum of the bob as seen from the road is increasing with momentum? If not, where is the external force which changes the linear momentum?