Home
Class 11
PHYSICS
Two particles of masses 1.0 kg and 2.0 k...

Two particles of masses 1.0 kg and 2.0 kg are placed at a separation of 50 cm. Assuming that the only forces acting on the particles are their mutual gravitation find the initial acceleration of the two particles.

Text Solution

Verified by Experts

Gravitational force between the two particles
`F = (Gm_(1)m_2)/r^2`
`F = (6.67xx10^(-11)xx1xx2)/((0.5)^2)=5.3xx10^(-10)N`
The acceleration of 1.0 Kg particle is
`a_(1)=F/m_1=(5.3 xx10^(-10))/1=5.3xx10^(-10)m//s^2`
It is towards the 2.0 Kg particle.
Promotional Banner

Similar Questions

Explore conceptually related problems

Three particles, each of mass m are fixed at the vertices of an equilateral triangle of side length a . The only forces acting on the particles are their mutual gravitational forces. Then answer the following questions. Force acting on particle C , due to particle A and B

Two particles of masses 1kg and 2kg are located at x=0 and x=3m . Find the position of their centre of mass.

Two particles of masses 1kg and 2kg are located at x=0 and x=3m . Find the position of their centre of mass.

Three particles, each of mass m are fixed at the vertices of an equilateral triangle of side length a . The only forces acting on the particles are their mutual gravitational forces. Then answer the following questions. The gravitational potential at O is

Three particles, each of the mass m are situated at the vertices of an equilateral triangle of side a . The only forces acting on the particles are their mutual gravitational forces. It is desired that each particle moves in a circle while maintaining the original mutual separation a . Find the initial velocity that should be given to each particle and also the time period of the circular motion. (F=(Gm_(1)m_(2))/(r^(2)))

Three particles, each of the mass m are situated at the vertices of an equilateral triangle of side a . The only forces acting on the particles are their mutual gravitational forces. It is desired that each particle moves in a circle while maintaining the original mutual separation a . Find the initial velocity that should be given to each particle and also the time period of the circular motion. (F=(Gm_(1)m_(2))/(r^(2)))

Two bodies of masses 1 kg and 6 xx 10^(24) kg are placed with their centres 6.38 xx 10^(6)m apart. Calculate the force of attraction between the two masses. Also find the initial acceleration of the two masses. [Assume that no other forces act on them]

Two particles of masses 2m and 3m are placed at separation d on a smooth surface. They move towards each other due to mutual attractive force. Find (a) acceleration of c.m. (b) Velocity of c.m. when separation between particles becomes d//3 . ( c) At what distance from the initial position of mass 2m , the particles collide.

Two spherical balls of mass 10 kg each are placed 10 cm apart. Find the gravitational force of attraction between them.

Two small bodies of masses 10 kg and 20 kg are kept a distance 1.0 m apart and released. Assuming that only mutual gravitational force are acting, find the speeds of the particles when the separation decreases to 0.5 m.