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As you have learnt in the text, a geosta...

As you have learnt in the text, a geostationary satellite orbits the earth at a height of nearly 36,000 km from the surface of the earth. What is the potential due to earth's gravity at the site of this satallite/ (Take the potential energy at inifinite to be zero). Mass of the earth=`6.0xx10^(24)kg`. radius=6400 km.

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Gravitational potential at height h from the surface of earth is
`V = -(GM)/((R+h))`
`=((-6.67xx10^(-11))xx(6xx10^(24)))/((6.4 xx10^6+3xx10^6))=-9.4 xx10^(6)J//kg`
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