Home
Class 11
PHYSICS
In planetary motion the areal velocity o...

In planetary motion the areal velocity of position vector of a planet depends on angular velocity `'omega'` and the distance of planet from sun (r). If so the correct relation for areal velocity is

A

`(dA)/(dt) prop omegar`

B

`(dA)/(dt) prop omega^(2)r`

C

`(dA)/(dt) prop omegar^(2)`

D

`(dA)/(dt) propsqrt(omegar)`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

In planetary motion the areal velocity of position vector of a planet depends on angular velocity (m) and the distance of the planet from sup (r). If so the correct relation for areal velocity is

The linear velocity perpendicular to radius vector of a particle moving with angular velocity omega=2hatK at position vector r=2hati+2hatj is

Derive an expression for the escape velocity of a body from any planet.

Which of the following graphs between the square of the time period and cube of the distance of the planet from the sun is correct ?

Which of the following graphs between the square of the time period and cube of the distance of the planet from the sun is correct ?

The correct relation between linear velocity overset rarr(v) and angular velocity overset rarr(omega) of a particle is

What is the direction of areal velocity of the earth around the sun?

If the angular velocity of a planet about its own axis is halved, the distance of geostationary satellite of this planet from the centre of the centre of the planet will become

Assertion : In planetary motion angular momentum of planet about centre of sun remains constant. But linear momentum of system does not remain constant. Reason : Net torque on planet any point is zero.

The position vector of a particle is r = a sin omega t hati +a cos omega t hatj The velocity of the particle is