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Two metal spheres of same material and r...

Two metal spheres of same material and radius ‘r. are in contact with each other. The gravitational force of attraction between the spheres is given by (k in a constant).

A

`F = Kr^4`

B

`F = k//r^2`

C

`F = k//4r^2`

D

`F = kr^2`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the gravitational force of attraction between two metal spheres of the same material and radius \( r \), we can follow these steps: ### Step 1: Calculate the Mass of Each Sphere The mass \( m \) of each metal sphere can be calculated using the formula for the volume of a sphere and the density of the material. The volume \( V \) of a sphere is given by: \[ V = \frac{4}{3} \pi r^3 \] Since density \( \rho \) is defined as mass per unit volume, we can express the mass as: \[ m = V \cdot \rho = \frac{4}{3} \pi r^3 \rho \] ### Step 2: Apply the Gravitational Force Formula The gravitational force \( F \) between two masses \( m_1 \) and \( m_2 \) separated by a distance \( d \) is given by Newton's law of gravitation: \[ F = \frac{G m_1 m_2}{d^2} \] In our case, both spheres have the same mass \( m \), and they are in contact with each other, so the distance \( d \) between their centers is \( 2r \) (the radius of one sphere plus the radius of the other). Thus, we can write: \[ F = \frac{G m^2}{(2r)^2} \] ### Step 3: Substitute the Mass into the Force Equation Now, substituting the expression for mass \( m \) from Step 1 into the force equation: \[ F = \frac{G \left(\frac{4}{3} \pi r^3 \rho\right)^2}{(2r)^2} \] ### Step 4: Simplify the Expression Now, we simplify the expression: \[ F = \frac{G \left(\frac{16}{9} \pi^2 r^6 \rho^2\right)}{4r^2} \] This simplifies to: \[ F = \frac{4G \pi^2 \rho^2 r^4}{9} \] ### Step 5: Define the Constant \( k \) To express the force in terms of a constant \( k \), we can define: \[ k = \frac{4G \pi^2 \rho^2}{9} \] Thus, the final expression for the gravitational force \( F \) becomes: \[ F = k r^4 \] ### Final Answer The gravitational force of attraction between the two spheres is given by: \[ F = k r^4 \]
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