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A satellite is revolving near the earth....

A satellite is revolving near the earth.s surface. Its orbital velocity depends on its mass .m. as

A

`m^0`

B

`m`

C

`m^2`

D

`m^3`

Text Solution

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The correct Answer is:
To solve the problem of determining how the orbital velocity of a satellite near the Earth's surface depends on its mass, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Forces Acting on the Satellite**: - A satellite in orbit experiences two main forces: the gravitational force (Fg) pulling it towards the Earth and the centripetal force (Fc) required to keep it in circular motion. 2. **Write the Expression for Gravitational Force**: - The gravitational force acting on the satellite can be expressed using Newton's law of gravitation: \[ F_g = \frac{G M m}{r^2} \] where: - \( G \) is the gravitational constant, - \( M \) is the mass of the Earth, - \( m \) is the mass of the satellite, - \( r \) is the distance from the center of the Earth to the satellite (approximately equal to the radius of the Earth when the satellite is near the surface). 3. **Write the Expression for Centripetal Force**: - The centripetal force required to keep the satellite in circular motion is given by: \[ F_c = \frac{m v_0^2}{r} \] where \( v_0 \) is the orbital velocity of the satellite. 4. **Set the Gravitational Force Equal to the Centripetal Force**: - For a satellite in stable orbit, the gravitational force must equal the centripetal force: \[ \frac{G M m}{r^2} = \frac{m v_0^2}{r} \] 5. **Cancel the Mass of the Satellite (m)**: - Since the mass \( m \) of the satellite appears on both sides of the equation, we can cancel it out (assuming \( m \neq 0 \)): \[ \frac{G M}{r^2} = \frac{v_0^2}{r} \] 6. **Rearrange the Equation to Solve for Orbital Velocity (v0)**: - Multiply both sides by \( r \): \[ \frac{G M}{r} = v_0^2 \] - Taking the square root gives us the expression for the orbital velocity: \[ v_0 = \sqrt{\frac{G M}{r}} \] 7. **Conclusion on the Dependence of Orbital Velocity on Mass**: - From the derived expression \( v_0 = \sqrt{\frac{G M}{r}} \), we can see that the orbital velocity \( v_0 \) does not depend on the mass \( m \) of the satellite. It only depends on the mass \( M \) of the Earth and the radius \( r \). ### Final Answer: The orbital velocity \( v_0 \) of a satellite near the Earth's surface is independent of its mass \( m \).
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