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When equal volumes of two substance are ...

When equal volumes of two substance are mixed, the specific gravity of the mixurie is 4. When equal weights of the same substance are mixed, the specific gravity of the mixture is 3. The soecufuc gravities of the two substance could be

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In case of mixture `rho_("mix")=(m_(1)+m_(2))/(v_(1)+v_(2))`
When equal volumes are mixed
`r=(4rho_(1)+vrho_(2))/(v+v)=(rho_(1)+rho_(2))/2`…..i
When equal mases are mixed.
`3=(m+m)/(m/(rho_(1))+m/(rho_(2)))=(2rho_(1)rho_(2))/(rho_(1)+rho_(2))`.....ii
Therefore from (i) and (ii) specific gravity of the metals are 2 and 6.
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