In Cavendish's experiment, let each small mass be 20g and each large mass be 5kg. The rod connecting the small massess is 50 cm long, while the small and the large speres are separated by 10.0 cm. The torsion constant is `4.8 xx 10^(-8) kg m^(2)s^(-2)` and the resulting angular deflection is `0.4^(@)`. Calculating the value of universal gravitational constant G from this data.

Explanation

To calculate the value of the universal gravitational constant \( G \) using the data provided from Cavendish's experiment, we will follow these steps:

### Step 1: Convert the Masses and Measurements to SI Units
- Small mass \( m = 20 \, \text{g} = 0.02 \, \text{kg} \)
- Large mass \( M = 5 \, \text{kg} \)
- Length of the rod \( l = 50 \, \text{cm} = 0.5 \, \text{m} \)
- Separation between small and large masses \( r = 10 \, \text{cm} = 0.1 \, \text{m} \)
- Angular deflection \( \theta = 0.4^\circ \)
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