Home
Class 11
PHYSICS
Find the value of 'g(i)' at a height of ...

Find the value of 'g(i)' at a height of 100 km (ii) at height 6400 km from the surface of the earth. (Radius of the earth = 6400 km, g on the surface of the earth `= 9.8 ms^(-2)`.

Text Solution

AI Generated Solution

To find the value of acceleration due to gravity \( g \) at different heights above the Earth's surface, we can use the following formulas: 1. For heights much smaller than the Earth's radius (like 100 km), we can use the formula: \[ g_h = g \left(1 - \frac{2h}{R}\right) \] where: - \( g_h \) = acceleration due to gravity at height \( h \) ...
Promotional Banner

Similar Questions

Explore conceptually related problems

Find out the capacitance of the earth ? (Radius of the earth = 6400 km)

Find the acceleration due to gravity at a point 64km below the surface of the earth. R = 6400 k, g on the surface of the earth = 9.8 ms^(-2) .

Find the percentage decrease in the weight of a body when taken 16 km below the surface of the earth. Take radius of the earth is 6400 km.

Find the depth at which the value of g becomes 25% of that at the surface of the earth. (Radius of the earth = 6400 km)

Calculate the height at which a man's weight becomes ( 4//9) of his weight on the surface of the earth, if the radius of the earth is 6400km.

A satellite is a at height of 25, 600 km from the surface of the earth. If its orbital speed is 3.536 km/s find its time period. (Radius of the earth = 6400 km)

Calculate the value of acceleration due to gravity at a point a. 5.0 km above the earth's surface and b. 5.0 km below the earth's surface. Radius of earth =6400 km and the value of g at the surface of the earth is 9.80 ms^2

What is the ratio of the weights of a body when it is kept at a height 500m above the surface of the earth and 500m below the surface of the earth, if the radius of the earth is 6400km.

A satellite is revolving round the earth at a height of 600 km. find a. The speed of the satellite and b. The time period of the satellite. Radius of the earth =6400 km and mass of the earth =6xx10^24kg .

Find the period of revolution of a satellite revolving the earth at a height of 200km above earth's surface ? Radius of earth = 6400 km