What is the work done in taking an object of mass 1kg from the surface of the earth to a height equal to the radius of the earth ?
(`G = 6.67 xx 10^(-11) Nm^(2)//Kg^(2)`, Radius of the earth = 6400 km, Mass of the earth `= 6 xx 10^(24) kg`.)

Explanation

To find the work done in taking an object of mass 1 kg from the surface of the Earth to a height equal to the radius of the Earth, we can follow these steps:

### Step 1: Understand the parameters
- Mass of the object, \( m = 1 \, \text{kg} \)
- Mass of the Earth, \( M = 6 \times 10^{24} \, \text{kg} \)
- Radius of the Earth, \( R = 6400 \, \text{km} = 6400 \times 10^3 \, \text{m} = 6.4 \times 10^6 \, \text{m} \)
- Gravitational constant, \( G = 6.67 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2 \)

...