Home
Class 11
PHYSICS
A satellite orbits the earth at a height...

A satellite orbits the earth at a height of 400km above the surface. How much energy must be expended to rocket the satellite out of the earth's gravitational influence? Mass of the satellite`=200`kg, mass of the earth=`6.0xx10^(24)`kg. radius of influcence? the earth`=6.4xx10^(6)m, G=6.67xx10(-11)Nm^(2)kg^(-2)`.

Text Solution

Verified by Experts

Total energy of orbiting satellite at a height
`h = (-GMm)/(2(R+h))`
Energy expended to rocket the satellite out of the earth.s gravitational field = -(total energy of the satellite)
`= (GMm)/(2(R+h)) = ((6.67 xx 10^(-11)) xx (6 xx 10^(24)) xx 200)/(2(6.4 xx10^(6) + 4 xx 10^(5))) = 5.9 xx 10^(9) J`
Promotional Banner

Similar Questions

Explore conceptually related problems

A satellite orbits the earth at a height of 400 km, above the surface. How much energy must be expended to rocket the satellite out of the earth's gravitational influence ? Mass of the satellite=200 kg, mass of the earth= 6.0xx10^(24) kg, radius of the earth= 6.4xx10(6) m, G= 6.67xx10^(-11)Nm^(2)Kg^(-2) .

A satellite orbits the earth at a height of 400 km, above the surface. How much energy must be expended to rocket the satellite out of the earth's gravitational influence ? Mass of the satellite=200 kg, mass of the earth= 6.0xx10^(24) kg, radius of the earth= 6.4xx10(6) m, G= 6.67xx10^(-11)Nm^(2)Kg^(-2) .

A satellite of a mass m orbits the earth at a height h above the surface of the earth. How much energy must be expended to rocket the satellite out of earth's gravitational influence? (where M_(E) and R_(E) be mass and radius of the earth respectively)

If a spaceship orbits the earth at a height of 500 km from its surface, then determine its (i) kinetic energy, (ii) potential energy, and (iii) total energy (iv) binding energy. Mass of the satellite = 300 kg, Mass of the earth = 6xx10^(24) kg , radius of the earth = 6.4 xx 10^(6) m, G=6.67 xx 10^(-11) "N-m"^(2) kg^(-2) . Will your answer alter if the earth were to shrink suddenly to half its size ?

A satellite orbits the earth at a height of 3.6xx10^(6)m from its surface. Compute it’s a kinetic energy, b. potential energy, c. total energy. Mass of the satellite =500kg mass of the earth =6xx10^(24) kg, radius of the earth =6.4xx10^(6), G=6.67xx10^(-11)Nm^(2)kg^(-2) .

A geostationary satellite orbits the Earth at a height of nearly 36,000 km from the surface of earth. What is the potential due to earth's gravity at the site of this satllite ? (Take the potential energy at infinity to be zero). Mass of the Earth = 6.0 xx 10^(24) kg , radius = 6400 km, G = 6.67 xx 10^(-11) Nm^(2)//kg^(2) .

What is the magnitude of the gravitational force between the Earth and a 1kg object on its surface ? (Mass of the earth is 6xx10^(24) kg and radius of the Earth is 6.4xx10^(6) m) .

Calculate the mass of sum if the mean radius of the earth's orbit is 1.5xx10^(8)km and G=6.67xx10^(-11)Nxxm^(2)//kg^(2)

A satellite is revolving round the earth at a height of 600 km. find a. The speed of the satellite and b. The time period of the satellite. Radius of the earth =6400 km and mass of the earth =6xx10^24kg .

A rocket is fired vertically with a speed of 5 kms^(-1) from the earth's surface. How far from the earth does the rocket go before returning to the earth ? Mass of earth= 6.0xx10^(24) kg, mean radius of the earth = 6.4xx10^(6) m, G= 6.67xx10^(-11)Nm^(2)Kg^(-2).