A satellite is revolving round the earth in a circular orbit with a velocity of 8km/s. at a height where acceleration due to gravity is `8m//s^(2)`. How high is the satellite from the earth ? (Take R = 6000 km)

Explanation

To solve the problem of finding the height of a satellite revolving around the Earth, we can follow these steps:

### Step 1: Understand the Given Data
- Velocity of the satellite, \( v = 8 \, \text{km/s} = 8 \times 10^3 \, \text{m/s} \)
- Acceleration due to gravity at the satellite's height, \( g_h = 8 \, \text{m/s}^2 \)
- Radius of the Earth, \( R = 6000 \, \text{km} = 6 \times 10^6 \, \text{m} \)

### Step 2: Use the Formula for Gravitational Acceleration
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