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A geostationary satellite orbits the earth at a height of nearly 36,000 km from the surface of earth. What is the potential due to earth's gravity at the site of this satellite? ( Take the potential energy at infinity to be zero). Mass of the earth `6.0 xx 10^(24) kg`, radius = 6400km.

Text Solution

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Gravitational potential at height hfrom the surface of earth is
`V = -(GM)/((R+h)) = (-6.67 xx 10^(-11) xx (6 xx 10^(24)))/((6.4 xx 10^(6) + 36 xx 10^(6))) = -9.4 xx 10^(6) J//kg`.
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