Home
Class 11
PHYSICS
A particle is projected from the ground ...

A particle is projected from the ground with velocity u making an angle `theta` with the horizontal. At half of its maximum heights,

A

its horizontal velocity is `u cos theta `

B

its vertical velocity is `(u sin theta)/(sqrt2)`

C

its velocity is `u((1+ cos^2 theta)/(2))^(1/2)`

D

all the above are true

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

A particle is fired from a point on the ground with speed u making an angle theta with the horizontal.Then

A particle is projected from the ground with velocity u at angle theta with horizontal. The horizontal range, maximum height and time of flight are R,H and T respectively. They are given by, R = (u^(2)sin 2 theta)/(g),H = (u^(2)sin^(2)theta)/(2g) and T = (2usin theta)/(g) Now keeping u as fixed, theta is varied from 30^(@) to 60^(@) . Then,

A particle is projected from ground with speed u and at an angle theta with horizontal. If at maximum height from ground, the speed of particle is 1//2 times of its initial velocity of projection, then find its maximum height attained.

A body is projected from ground with velocity u making an angle theta with horizontal. Horizontal range of body is four time to maximum height attained by body. Find out (i) angle of projection (ii) Range and maximum height in terms of u (iii) ratio of kinetic energy to potential energy of body at maximum height

A particle is projected with a velocity u making an angle theta with the horizontal. At any instant its velocity becomes v which is perpendicular to the initial velocity u. Then v is

A particle is projected from a point O with velocity u in a direction making an angle alpha upward with the horizontal. AT P , it is moving at right angles to its initial direction of projection . Its velocity at P is .

STATEMENT-1: A body is projected from the ground with a velocity v at an angle with the horizontal direction, it reaches a maximum height (H) and reaches the ground after a time T = 2u sin theta//g STATEMENT-2: The vertical and horizontal motions can be treated independently

A particle is projected from a point P with a velocity v at an angle theta with horizontal. At a certain point Q it moves at right angles to its initial direction. Then

A particle is projected from a point P with a velocity v at an angle theta with horizontal. At a certain point Q it moves at right angles to its initial direction. Then

A particle is projected form ground with velocity u ar angle theta from horizontal. Match the following two columns.