A projectile is given an initial velocit...

A projectile is given an initial velocity of `(hati+2hatj) m//s,` where `hati` is along the ground and `hatj` is along the vertical. If `g = 10 m//s^(2),` the equation of its trajectory is:

`y = x -5 x^2`

`y = 2x - 5x^2`

`4y = 2x - 5x^2`

`4y = 2x - 25 x^2`

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