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A particle moves in a circular path suc...

A particle moves in a circular path such that its speed v varies with distance as `v=alphasqrts` where `alpha` is a positive constant. Find the acceleration of particle after traversing a distance S?

A

`alpha^2 sqrt(1/4 - S^2/R^2)`

B

`alpha^2 sqrt(1/4+S^2/R^2)`

C

`alpha sqrt(1/2 + S^2/R^2)`

D

`alpha^2 sqrt(1/2 + S^2/R^2)`

Text Solution

Verified by Experts

The correct Answer is:
B
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