Home
Class 11
PHYSICS
A body of mass 5 kg is at rest. Three fo...

A body of mass 5 kg is at rest. Three force `F_(1) = 10 N` due North `F_2=10N` along East and `F_(3) = 10 sqrt(2) N` along N-W act on it simultaneously. The acceleration produced in the body is,

A

`4ms^(-2)` along north

B

`2ms^(-2)` along north

C

`4ms^(-2)` along east

D

`2ms^(-2)` along east

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

A force of 10 N acts on a body of mass 5 kg. Find the acceleration produced.

A force of 15 N acts on a body of mass 2 kg. Calculate the acceleration produced.

A force of 15 N acts on a body of mass 2 kg. Calculate the acceleration produced.

The acceleration of 10 kg block when F = 30 N is

A block of mass m = 10 kg is pulled by a force F = 100 N at an angle theta=30^(@) with the horizontal along a smooth horizontal surface. What is the acceleration of the block? (g = 10m//s^(2))

When a force F acts on a body of mass m the acceleration product in the body is a . If three equal forces F_(1)=F_(2)=F_(3)=F act on the same body as shown in figure the acceleration produced is

A cubical block is experiencing three forces F_(1) = 20 N acts at angle 45^(@) with horizontal and lies in diagram plane of the cube F_(2) = 30 N acts along y- axis and F_(3) = 40 N acts in x- direction as shown in fig find the friction force acting on the block if it is at rest

A 10 N force is applied on a body produces an acceleration of 1 m//s^(2) . The mass of the body is

Two forces F_(1)=1N and F_(2)=2N act along the lines x=0 and y=0, respectively. Then find the resultant of forces.

A body of mass 5 kg is acted upon by two perpendicular forces 8 N and 6 N Give the magnitude and direction of the acceleration of the body.