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A car starts from rest and moves with un...

A car starts from rest and moves with uniform acceleration 'a', At the same instant from the same point a bike crosses with a uniform velocity 'u'. When and where will they meet ? What is the velocity of car with respect to the bike at the time of meeting?

Text Solution

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Let the car and bike will meet after coving a distance S in a time .t. sec.
For car
`S=(1)/(2)at^(2)……(1)`
for bike
`s=ut……(2)`
Since they cover same distance
`ut=(1)/(2)at^(2)impliest=(2u)/(a)`
The car and bike will meet after a time of `(2u)/(a)` sec.
The velocity of car after .t. sec is
`V_(car)=at=a((2u)/(a))=2u`
The velocity of car w.r.t bike is `V_(rel)=2u-u=u`.
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