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Displacement-time equation of a particle...

Displacement-time equation of a particle execution SHM is x=A sin(`omegat+pi/6)`
Time taken by the particle to go directly from
`x = -A/2 to x = + A/2 is `

Text Solution

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Period of oscillation is `T=(2pi)/(omega)`
Now time taken in going from mean position to `x=A/2` or from `x=A/2` to mean position comes out to be `T/12`. Therefore the desired time will be
`t=2(T/12)=T/6=(pi)/(3pomega)`
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