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Frequency of a particle executing SHM is...

Frequency of a particle executing SHM is 10 Hz. The particle is suspended from a vertical spring. At the highest point of its oscillation the spring is unstretched. Maximum speed of the particle is (g=10m/`s^(2)`

Text Solution

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Mean position of the particle is `(mg)/k` distance below unstretched position of spring. Therefore, amplitude of oscillation is
`A=(mg)/k" "omega=sqrt(k/m)=2pif=20pi`
`:.m/k=1/(400pi^(2))`
Therefore the maximum speed of particle will be
`v_("max")=A omega=(g/(400pi^(2)))(20pi)=1/(2pi)m//s`
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