Home
Class 11
PHYSICS
A mass M is suspended from a massless sp...

A mass `M` is suspended from a massless spring. An additional mass `m` stretches the spring further by a distance `x`. The combined mass will oscillate with a period

A

`T= 2pi sqrt((mg)/(x(M+m)))`

B

`T= 2pi sqrt(((M+m)x)/(mg))`

C

`T= 2pi sqrt((M+m)/(mgx))`

D

`T= 2pi sqrt((mgx)/(M+m))`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

A mass M is suspended from a light spring. An additional mass m added to it displaces the spring further by distance x then its time period is

A block with a mass of 3.00 kg is suspended from an ideal spring having negligible mass and stretches the spring by 0.2 m . (a) What is the force constant of the spring? (b) What is the period of oscillation of the block if it is pulled down and released ?

A block with a mass of 3.00 kg is suspended from an ideal spring having negligible mass and stretches the spring by 0.2 m . (a) What is the force constant of the spring? (b) What is the period of oscillation of the block if it is pulled down and released ?

A mass M is suspended from a spring of negiliglible mass the spring is pulled a little and then released so that the mass executes simple harmonic oscillation with a time period T If the mass is increases by m the time period because ((5)/(4)T) ,The ratio of (m)/(M) is

A block of M is suspended from a vertical spring of mass m as shown in the figure. When block is pulled down and released the mass oscillates with maximum velocity v .

Mass suspended to a spring is pulled down by 2.5 cm and let go. The mass oscillates with an amplitude of

A mass M is suspended from a spring of negligible mass. The spring is pulled a little then released, so that the mass executes simple harmonic motion of time period T . If the mass is increased by m , the time period becomes (5T)/(3) . Find the ratio of m//M .

A mass is suspended from a vertica spring which is executing SHM of frequency 5 Hz. The spring is unstretched at the highest point of oscillation. Maximum speed of the mass is (take, acceleration due to gravity, g=10m//s^(2) )

One mass m is suspended from a spring. Time period of oscilation is T. now if spring is divided into n pieces & these are joined in parallel order then time period of oscillation if same mass is suspended.

Let T_(1) and T_(2) be the periods of springs A and B when mass M is suspended from one end of each spring. If both springs are taken in series and the same mass M is, suspended from the séries combination, the time period is T, then