Home
Class 11
PHYSICS
Calculate the height at which the value ...

Calculate the height at which the value of acceleration due to gravity becomes 50% of that at the earth.
(Radius of the earth = 6400 km)

Text Solution

Verified by Experts

g at height, `g_(h) = (g)/((1+(h)/(R))^(2))`
In this problem, `g_(h) = (50)/(100)g = 0.5g`
`0.5 g = (g)/((1+(h)/(R))^(2)) rArr (1+(h)/(R))^(2) = (g)/(0.5 g) = 2`
`1+(h)/(R) = sqrt(2), (h)/(R) = sqrt(2) - 1 rArr` the height,
`h = 0.414 R = 0.414 xx 6400 = 2650km`.
Promotional Banner

Similar Questions

Explore conceptually related problems

The value of acceleration due to gravity at the surface of earth

Find the depth at which the value of g becomes 25% of that at the surface of the earth. (Radius of the earth = 6400 km)

The depth d , at which the value of acceleration due to gravity becomes 1/n times the value at the surface is (R = radius of the earth)

Acceleration due to gravity is ‘ g ’ on the surface of the earth. The value of acceleration due to gravity at a height of 32 km above earth’s surface is (Radius of the earth = 6400 km )

The value of acceleration due to gravity will be 1% of its value at the surface of earth at a height of (R_(e )=6400 km)

Find out the capacitance of the earth ? (Radius of the earth = 6400 km)

The height of the point vertically above the earth's surface, at which acceleration due to gravtiy becomes 1% of its value at the surface is (Radius of the earth =R)

The depth 'd' at which the value of acceleration due to gravity becomes (1)/(n) times the value at the earth's surface is (R = radius of earth)

Assuming earth to be a sphere of radius 6400km, calculate the height above the earth's surface at which the value of acceleration due to gravity reduces to half its value on the erath's surface.

At what height the acceleration due to gravity decreases by 36% of its value on the surface of the earth ?